x^2-16x^2+64=0

Solution for x^2-16x^2+64=0 equation:

x^2-16x^2+64=0

We add all the numbers together, and all the variables

-15x^2+64=0

a = -15; b = 0; c = +64;
Δ = b2-4ac
Δ = 02-4·(-15)·64
Δ = 3840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3840}=\sqrt{256*15}=\sqrt{256}*\sqrt{15}=16\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{15}}{2*-15}=\frac{0-16\sqrt{15}}{-30}
=-\frac{16\sqrt{15}}{-30}
=-\frac{8\sqrt{15}}{-15}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{15}}{2*-15}=\frac{0+16\sqrt{15}}{-30}
=\frac{16\sqrt{15}}{-30}
=\frac{8\sqrt{15}}{-15}
$